ExVrp solves vehicle routing problems through PyVRP's C++ core. You build an ExVrp.Model, call
ExVrp.solve/2, and read routes off the resulting solution.
model =
ExVrp.Model.new()
|> ExVrp.Model.add_depot(x: 0, y: 0)
|> ExVrp.Model.add_vehicle_type(num_available: 2, capacity: [100], time_windows: [{0, 28_800}])
|> ExVrp.Model.add_client(x: 10, y: 10, delivery: [20], service_duration: 300)
|> ExVrp.Model.add_client(x: 20, y: 0, delivery: [30], service_duration: 300)
{:ok, result} = ExVrp.solve(model, max_runtime: 30_000, seed: 42)
result.best.routes #=> [[1, 2]]
result.best.distance #=> 48
result.best.is_feasible #=> trueLocation indices are offset by the depot count
This is the single most common source of wrong answers. Clients are stored in their own list, but
every index the solver reports or accepts — route visits, client-group members, same-vehicle group
members — is a location index, and locations are [depots..., clients...]:
location_idx = ExVrp.Model.num_depots(model) + client_idx
client_idx = location_idx - ExVrp.Model.num_depots(model)With one depot, routes: [[1, 2]] means the first and second clients, not the second and third. Map
back through your own index before showing anything to a user. ExVrp.Model.num_locations/1 gives
depots + clients, which is also the required size of every matrix.
Add every depot before any client
add_depot/2 shifts existing client-group and same-vehicle-group indices to keep them pointing at
the same clients. It works, but it means group indices depend on the order you called things. Build
in this order and the question never comes up:
Model.new()
|> Model.add_depot(...) # 1. all depots
|> Model.add_vehicle_type(...) # 2. all vehicle types
|> Model.add_client(...) # 3. clients, with their groupsCapacity dimensions must match everywhere
Vehicle capacity and client delivery/pickup are lists, one entry per dimension (weight,
volume, pallets, …). Validation compares every client against the first vehicle type's
dimension count, and delivery/pickup default to [0] — a one-dimensional default that fails
validation the moment your vehicles carry two dimensions. Pass a full-width list on every client:
|> Model.add_vehicle_type(num_available: 3, capacity: [1000, 50], time_windows: [{0, 28_800}])
|> Model.add_client(x: 1, y: 1, delivery: [200, 10], pickup: [0, 0])Vehicle time windows: pass :time_windows, never tw_early/tw_late
VehicleType.new/1 raises ArgumentError on :tw_early, :tw_late or :forbidden_windows — they
are derived, not inputs. Give it the windows the vehicle is available, and it merges them and
derives the gaps as forbidden windows:
Model.add_vehicle_type(model,
num_available: 2,
capacity: [100],
time_windows: [{0, 500}, {600, 1000}]
)
# => tw_early: 0, tw_late: 1000, forbidden_windows: [{500, 600}]Clients are the opposite: they take tw_early/tw_late directly (tw_late defaults to
:infinity), plus release_time for "not available before".
Optional clients need required: false and a prize
A client defaults to required: true, which makes it a hard constraint — if it cannot be served,
the whole solve is infeasible rather than dropping that client. To let the solver choose, mark it
optional and price it:
Model.add_client(model, x: 50, y: 50, delivery: [10], required: false, prize: 5000)The prize is what the solver gives up by skipping the client, so it is the knob that decides
"serve it" against "drive there". A required: false client with prize: 0 will essentially always
be dropped.
Client groups express "one of these"
A group with required: false becomes mutually exclusive by default (mutually_exclusive defaults
to not required), meaning at most one member is visited — the way to model alternative time slots
or alternative addresses for the same job. Members must be optional too: adding a required: true
client to a mutually exclusive group raises ArgumentError.
{model, group} = Model.add_client_group(model, required: false)
model =
model
|> Model.add_client(x: 1, y: 1, group: group, required: false, prize: 100)
|> Model.add_client(x: 2, y: 2, group: group, required: false, prize: 100)Use Model.add_same_vehicle_group/3 for the different constraint "if these are visited, one vehicle
does all of them" — it takes client structs, not indices, and converts them for you.
Custom matrices are per profile, and their diagonal must be zero
Without matrices, ExVrp computes Euclidean distance from coordinates — fine for tests, wrong for
road networks. Supply one matrix per profile; a vehicle type's profile: is an index into that
list, which is how you give a van and a bike different travel times over the same locations:
model
|> Model.set_distance_matrices([van_distances, bike_distances])
|> Model.set_duration_matrices([van_durations, bike_durations])
|> Model.add_vehicle_type(num_available: 2, capacity: [100], time_windows: [{0, 28_800}], profile: 1)Each matrix must be exactly num_locations × num_locations, ordered [depots..., clients...], with
a zero diagonal. Duration matrices default to the distance matrices when omitted, which is only
correct if your distances are already expressed in time.
The cost model lives on the vehicle type, and its terms are not on the same scale
What the solver minimises is set per vehicle type, not per solve:
| Field | Default | Term it prices |
|---|---|---|
unit_distance_cost | 1 | distance travelled |
unit_duration_cost | 0 | duration, including service time |
fixed_cost | 0 | each vehicle the solution uses |
Plus the prizes of any optional client left unserved. Duration is free by default — if you
want the solver to care about time rather than kilometres, you must set unit_duration_cost
yourself.
The trap is magnitude. Distance and duration are in unrelated units, and duration carries every
client's service_duration, so it is usually far the larger number. On a two-client instance with
service_duration: 300:
# distance 48, duration 648 (48 travel + 600 service)
unit_distance_cost: 1 # => cost 48
unit_distance_cost: 1, fixed_cost: 1000 # => cost 1048
unit_distance_cost: 1, unit_duration_cost: 2 # => cost 1344 (2 × 648 swamps the 48)Price the terms against each other's actual magnitudes on your own data, or one of them silently
becomes the whole objective. IteratedLocalSearch.Result.cost/1 reports this total, which is why
it is not a distance.
Overtime needs two fields, and shift_duration alone is a hard cap
Three vehicle-type fields interact here, and only two of them are on the same axis:
| Field | Axis | Meaning |
|---|---|---|
shift_duration | duration | nominal shift, and the baseline duration-based overtime counts from |
max_duration | duration | hard cap on route duration; defaults to shift_duration |
overtime_start | clock | contracted end of shift, same axis as :time_windows |
Both duration fields measure elapsed time rather than time worked — see the next section, which is the single most common way these get misused.
max_duration defaulting to shift_duration is the part that catches people out. It means
unit_overtime_cost on its own does nothing:
# Inert. The route is hard-capped at 480, so duration never exceeds shift_duration
# and duration-based overtime is always 0.
Model.add_vehicle_type(model, shift_duration: 480, unit_overtime_cost: 10)
# Works. Up to 60 units past the nominal shift, priced at 10 each.
Model.add_vehicle_type(model, shift_duration: 480, max_duration: 540, unit_overtime_cost: 10)Overtime is then max(0, duration - shift_duration) — it measures how long the vehicle worked,
so a route that starts late but runs only seven hours incurs none.
If your drivers are contracted until a wall-clock time rather than for a number of hours, that is a
different rule and needs overtime_start:
Model.add_vehicle_type(model,
time_windows: [{0, 86_400}],
shift_duration: 28_800,
max_duration: :infinity,
overtime_start: 57_600, # 16:00
unit_overtime_cost: 10
)Overtime becomes max(0, route_end - overtime_start). A driver who runs 09:00–17:00 has worked an
hour of overtime even though the route lasted exactly the nominal eight. Setting overtime_start
switches the rule over completely — shift_duration stops feeding the overtime calculation and
does nothing but seed the max_duration default.
Read the result with ExVrp.Solution.overtime/1 or ExVrp.Route.overtime/1.
Duration caps measure elapsed time, not time worked
shift_duration, max_duration and ExVrp.Route.duration/1 all measure elapsed time: route
start to route end, with idle time included. None of them caps how long the driver actually worked.
That distinction is invisible until a client's time window forces a wait, and then it inverts the answer. A driver doing 300 units of driving across a day with a 600-unit gap in the middle:
# elapsed 900, wait 600, actually worked 300
max_duration: 500 # => INFEASIBLE, despite only 300 units worked
max_duration: 1500 # => feasibleSo a working day made of two short shifts separated by a long gap breaches an elapsed cap that the driver's real hours would clear — and conversely, an elapsed cap generous enough to allow that day also permits a route that genuinely works the full span.
There is no "no more than N hours worked per day" constraint. If that is what you need, the solver cannot enforce it; measure it after the fact and reject or re-plan yourself:
worked = ExVrp.Route.duration(route) - ExVrp.Route.wait_duration(route)
# equivalently: ExVrp.Route.travel_duration(route) + ExVrp.Route.service_duration(route)Warm-starting with :initial_routes
If you already have a plan — last night's routes, or an existing schedule you are inserting new orders into — seed the solver instead of cold-starting:
ExVrp.solve(model, initial_routes: [[1, 2, 3], [], [4, 5]])Position in the outer list is the vehicle type index; empty inner lists mean that vehicle type
is unused. The inner lists are location indices, the same numbering result.best.routes gives
back, so a solution can be fed straight back in. An invalid warm start is not an error: the solver
logs a warning and falls back to an empty start, so check your logs rather than assuming it took.
Multi-trip routes need reload_depots
A vehicle returns to a depot mid-route and reloads only if you say where:
Model.add_vehicle_type(model,
num_available: 2,
capacity: [100],
time_windows: [{0, 28_800}],
reload_depots: [0],
max_reloads: 2
)reload_depots defaults to [], which disables reloading entirely — a vehicle is then capped at
one load for the whole shift, and an instance whose total demand exceeds one load comes back
infeasible rather than reloading.
Count the reload stops with ExVrp.Route.num_trips/1. Do not read route.trips: the field is
declared on the struct but ExVrp.Solution.routes/1 never fills it, so it is always [] even on a
route that made three trips.
Validate before you blame the solver
ExVrp.solve/2 validates first and returns {:error, reasons} — a list of human-readable strings —
rather than solving something malformed. When a model misbehaves, call it directly:
case ExVrp.Model.validate(model) do
:ok -> :ready
{:error, reasons} -> IO.inspect(reasons)
endIt catches mismatched capacity dimensions, tw_late < tw_early, release times past the window, bad
depot/reload indices, wrong matrix sizes, non-zero diagonals, and required clients in exclusive
groups.
Reading the result
solve/2 returns {:ok, result}; the solution is result.best:
result.best.routes— list of visit lists, in location indices (see above)result.best.distance,.duration,.num_clientsresult.best.is_feasible— false means constraints are violated; do not ship the planresult.best.is_complete— false means required clients were left unservedExVrp.Solution.routes/1— richerExVrp.Routestructs carryingvisits,vehicle_type,start_depotandend_depot, plus NIF-backed queries likeRoute.distance/1,Route.feasible?/1andRoute.num_trips/1. Only those four struct fields are populated; everything else comes from the query functions.
Check is_feasible before reading distances. An infeasible solution still reports numbers.
Stopping and reproducibility
Defaults: max_iterations: 10_000, unlimited runtime, num_starts: :auto
(div(System.schedulers_online(), 2) independent parallel starts, best one wins).
- Bound wall-clock work with
max_runtime:(milliseconds), not iterations — iteration cost scales with instance size, so a fixed iteration budget means wildly different runtimes across instances. - The two runtime knobs use different units. The
:max_runtimeoption is milliseconds;StoppingCriteria.max_runtime/1is seconds, as a float, matching PyVRP'sMaxRuntime. Passing30_000to the criterion asks for eight hours. seed:makes a solve reproducible, multi-start included — starts are seeded deterministically from it. Addnum_starts: 1when you also need results to match across machines::autoderives the start count fromSystem.schedulers_online(), so a 8-core box and a 32-core box explore differently.ExVrp.StoppingCriteriacomposes conditions:StoppingCriteria.any([max_runtime(60.0), max_iterations(5000)]), orno_improvement(1000).on_progress:takes a callback receiving progress maps, for logging long solves.log_label:namespaces this solve's log lines. Start indices only distinguish chains within onesolve/2, so a host running several solves at once sees the same[exvrp start 0..3]labels from all of them;log_label: "relaxed_15"makes them tellable apart.
Note that IteratedLocalSearch.Result.cost/1 returns the full objective — see the cost model above
— and :infinity when infeasible. Do not read it as a distance.